Back to Home Exam Preparation
Question

An equilateral triangle has sides of length 8 cm8\text{ cm}. Find its perpendicular height$

Verified Answer

43 cm4\sqrt{3}\text{ cm}

Explanation & Step-by-Step Solving

Context: Dropping a vertical line bisects the base into two parts of 4 cm4\text{ cm} each. Using Pythagoras' theorem:h=82−42=64−16=48=16×3=43 cmh = \sqrt{8^2 - 4^2} = \sqrt{64 - 16} = \sqrt{48} = \sqrt{16 \times 3} = 4\sqrt{3}\text{ cm}

Topic Tags

Exam aration and answersWAEC Exam arationJAMB Exam arationacademic problems

Related Past Questions

16 JAMB UTME Choose the option nearest in meaning to adroit

Exam Preparation

What is the historical significance of the 'Golden Stool' (Sika Dwa Kofi) in the Ashanti Kingdom?

Exam Preparation

Find the gradient (slope) of the line joining points A(2,5)A(2, 5) and B(4,13)B(4, 13)

Exam Preparation

Ready to practice more questions?

Access hundreds of interactive flashcards, trivia challenges, and math tests directly on our main dashboard feed.

Start Interactive Practice