African Shorts

Quick culture snippets, idioms, and riddles.

Exam Preparation

Find the simple interest on ₦20,000 for 3 years at 5%5\% per annum

Verified Answer

₦3,000

Solving: Formula=P×R×T100=20000×5×3100=200×15=3,000\text{Formula} = \frac{P \times R \times T}{100} = \frac{20000 \times 5 \times 3}{100} = 200 \times 15 = ₦3,000

Exam Preparation

Find the lowest common multiple (LCM) of 12, 18, and 30.

Verified Answer

180

Context: Find prime factors: 12=22×312 = 2^2 \times 3, 18=2×3218 = 2 \times 3^2, 30=2×3×530 = 2 \times 3 \times 5. Take the highest power of each factor:22×32×5=4×9×5=1802^2 \times 3^2 \times 5 = 4 \times 9 \times 5 = 180

Exam Preparation

Calculate the length of an arc which subtends an angle of 6060^\circ at the centre of a circle of radius 7 cm7\text{ cm}. [Take π=227\pi = \frac{22}{7}]

Verified Answer

7.33 cm7.33\text{ cm}

Context: Using the arc length formula L=θ360×2πrL = \frac{\theta}{360} \times 2\pi r:L=60360×2×227×7=16×44=2237.33 cmL = \frac{60}{360} \times 2 \times \frac{22}{7} \times 7 = \frac{1}{6} \times 44 = \frac{22}{3} \approx 7.33\text{ cm}

Exam Preparation

Find the value of yy if log3(y4)=2\log_3(y - 4) = 2

Verified Answer

13

Context: Change the log equation into exponential format:y - 4 = 3^2$$$$y - 4 = 9 \implies y = 13

Exam Preparation

Simplify the expression: 7527+12\sqrt{75} - \sqrt{27} + \sqrt{12}.

Verified Answer

434\sqrt{3}

Solving: Simplify to basic surds: 25×39×3+4×3=5333+23=43\sqrt{25 \times 3} - \sqrt{9 \times 3} + \sqrt{4 \times 3} = 5\sqrt{3} - 3\sqrt{3} + 2\sqrt{3} = 4\sqrt{3}

Exam Preparation

If 5018=k2\sqrt{50} - \sqrt{18} = k\sqrt{2}, find the value of kk

Verified Answer

2

Context: Simplify each surd by finding perfect square factors:\sqrt{50} = \sqrt{25 \times 2} = 5\sqrt{2}$$$$\sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2}Subtracting them yields:5232=22    k=25\sqrt{2} - 3\sqrt{2} = 2\sqrt{2} \implies k = 2

Exam Preparation

In a class of 40 students, 25 offer Mathematics and 18 offer Physics. If 7 students offer both subjects, find how many offer neither.

Verified Answer

4

Context: Let xx be the number of students offering neither. Using set theory rules:\text{Total} = (\text{Math only}) + (\text{Physics only}) + (\text{Both}) + (\text{Neither})$$$$40 = (25 - 7) + (18 - 7) + 7 + x \implies 40 = 18 + 11 + 7 + x$$$$40 = 36 + x \implies x = 4

Exam Preparation

The third term of a Geometric Progression (G.P.) is 18 and its fourth term is 54. Find the first term

Verified Answer

2

Solving: Common ratio r=T4T3=5418=3r = \frac{T_4}{T_3} = \frac{54}{18} = 3. T3=ar2=18    a(32)=18    9a=18    a=2T_3 = a \cdot r^2 = 18 \implies a \cdot (3^2) = 18 \implies 9a = 18 \implies a = 2.

Exam Preparation

Find the Highe6st Common Factor (HCF) of 18, 24, and 42.

Verified Answer

66

Solving: Find the prime factors: 18=2×3218 = 2 \times 3^2, 24=23×324 = 2^3 \times 3, 42=2×3×742 = 2 \times 3 \times 7. The common factors are 2 and 3. HCF=2×3=6\text{HCF} = 2 \times 3 = 6

Exam Preparation

Solve the linear equation: 4(x3)=2x+84(x - 3) = 2x + 8

Verified Answer

x=10x = 10

Solving: Expand the brackets: 4x12=2x+84x - 12 = 2x + 8. Collect like terms: 4x2x=8+12    2x=20    x=104x - 2x = 8 + 12 \implies 2x = 20 \implies x = 10

Exam Preparation

Find the value of xx if 3x=1220\frac{3}{x} = \frac{12}{20}.

Verified Answer

5

Solving: Cross-multiply: 12x=3×20    12x=60    x=6012=512x = 3 \times 20 \implies 12x = 60 \implies x = \frac{60}{12} = 5.

Exam Preparation

Find the gradient of the curve y=x24xy = x^2 - 4x at the point where x=5x = 5

Verified Answer

6

Context: Differentiate the curve equation to find the general gradient function: dydx=2x4\frac{dy}{dx} = 2x - 4. Now substitute the target point coordinate x=5x = 5:Gradient=2(5)4=104=6\text{Gradient} = 2(5) - 4 = 10 - 4 = 6

Idioms & Meanings

I have cities, but no houses. I have mountains, but no trees. What am I?

Verified Answer

A map

A map has a lot of things on it but lack

Exam Preparation

If the gradient of a straight line passing through (3,y)(3, y) and (5,8)(5, 8) is 22, find the value of yy

Verified Answer

4

Context: The gradient formula is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}:2=8y53    2=8y2    4=8y    y=42 = \frac{8 - y}{5 - 3} \implies 2 = \frac{8 - y}{2} \implies 4 = 8 - y \implies y = 4

Exam Preparation

A car travels at a uniform speed of 80km/h80\text{km/h}. What distance does it cover in 45 minutes?

Verified Answer

60km60\text{km}

Solving: Convert 45 minutes to hours: 4560=0.75 hours\frac{45}{60} = 0.75\text{ hours}. Distance=Speed×Time=80×0.75=60km\text{Distance} = \text{Speed} \times \text{Time} = 80 \times 0.75 = 60\text{km}.

Exam Preparation

Solve the inequality: 3x5>7x+113x - 5 > 7x + 11

Verified Answer

x<4x < -4

Solving: Rearrange variables: 511>7x3x    16>4x    4>x-5 - 11 > 7x - 3x \implies -16 > 4x \implies -4 > x. Flip direction to match standard layout: x<4x < -4

Jokes & Witty Words

Why did the student bring a heavy blanket into the exam hall for their West African history paper?

Verified Answer

Because they heard the questions on the ancient Mali Empire were going to be absolutely freezing cold!

😂 Wit: Lighthearted school humor

Riddles & Brainteasers

Two legs sat on three legs eating one leg. Along came four legs and snatched one leg. Up jumped two legs, picked up three legs, and threw it at four legs to get one leg back. What is happening?

Verified Answer

A person (2 legs) sitting on a stool (3 legs) eating a chicken leg (1 leg). A dog (4 legs) steals the chicken leg, and the person throws the stool at the dog.

🧠 Riddle: Classic logic puzzle to test text-wrapping inside your grid cards

Exam Preparation

A shadow cast by a flagpole is 10m10\text{m} long. If the angle of elevation of the sun is 6060^\circ, find the height of the flagpole.

Verified Answer

103m10\sqrt{3}\text{m}

Solving: tan(60)=Height10    3=Height10    Height=103m\tan(60^\circ) = \frac{\text{Height}}{10} \implies \sqrt{3} = \frac{\text{Height}}{10} \implies \text{Height} = 10\sqrt{3}\text{m}.

Exam Preparation

Find the range of values of xx for which 3x75x+33x - 7 \leq 5x + 3

Verified Answer

x5x \geq -5

Context: Collect like terms to solve the inequality:735x3x    102x-7 - 3 \leq 5x - 3x \implies -10 \leq 2xDividing both sides by 2 yields:5x which reads as x5-5 \leq x \text{ which reads as } x \geq -5

Exam Preparation

Find the perimeter of a rectangular football field whose length is 90m90\text{m} and width is 60m60\text{m}

Verified Answer

300m300\text{m}

Solving: Perimeter=2(L+W)=2(90+60)=2(150)=300m\text{Perimeter} = 2(L + W) = 2(90 + 60) = 2(150) = 300\text{m}

Exam Preparation

Figures of Speech: I have told you a thousand times!" is an example of?

Verified Answer

Hyperbole

Explanation: An intentional and obvious exaggeration

Exam Preparation

If N520\text{N}520 is shared between Chidi and Tunde in the ratio 5:85:8, how much does Tunde receive?

Verified Answer

N320\text{N}320

Context: Total ratio parts =5+8=13= 5 + 8 = 13. Tunde's share is:813×520=8×40=320\frac{8}{13} \times 520 = 8 \times 40 = 320

Exam Preparation

Figures of Speech: The stars danced in the sky.

Verified Answer

Personification

The stars are given the human ability to dance

Exam Preparation

Find the median of this data distribution: 14,9,12,16,20,11,714, 9, 12, 16, 20, 11, 7

Verified Answer

12

Solving: Sort dataset in ascending order: 7,9,11,12,14,16,207, 9, 11, \mathbf{12}, 14, 16, 20. The middle value positions at index 4, which is exactly 12

Exam Preparation

Find the median of the following distribution of numbers: 7,3,9,5,6,3,87, 3, 9, 5, 6, 3, 8.

Verified Answer

6

Context: First, rearrange the list of numbers in ascending order: 3,3,5,6,7,8,93, 3, 5, 6, 7, 8, 9. Since there are 7 terms, the middle (4th) position value is the median:Median=6\text{Median} = 6

Exam Preparation

Solve for xx in the equation: 23x1=322^{3x-1} = 32

Verified Answer

x=2x = 2

Solving: Convert 32 to base 2: 32=2532 = 2^5. Equate bases: 23x1=25    3x1=5    3x=6    x=22^{3x-1} = 2^5 \implies 3x - 1 = 5 \implies 3x = 6 \implies x = 2.

Exam Preparation

Vocabulary: A 'neophyte' is a _________

Verified Answer

Beginner / Novice

Someone new to a subject or belief

Exam Preparation

Expand the algebraic expression: (2x+3)(x4)(2x + 3)(x - 4)

Verified Answer

2x25x122x^2 - 5x - 12

Solving: Expand via FOIL method: 2x(x)+2x(4)+3(x)+3(4)=2x28x+3x12=2x25x122x(x) + 2x(-4) + 3(x) + 3(-4) = 2x^2 - 8x + 3x - 12 = 2x^2 - 5x - 12

Exam Preparation

JAMB UTME Select the correct option: The disciplinary committee has submitted _______ report

Verified Answer

It's

UTME Pronoun Usage (Collective noun "committee" takes the singular neuter possessive "its")

Jokes & Witty Words

How do you know an African mother is about to deploy the "ultimate weapon" during an argument?

Verified Answer

When she starts a sentence with "Is it me you are looking at like that?" or unties her wrapper to retie it tighter.

😂 Humour: Relatable observational comedy to test how well the UI presents multi-line answers

Exam Preparation

Vocabulary: What does 'ambiguous' mean?

Verified Answer

Open to more than one interpretation

"Each" is singular and takes a singular verb.

Exam Preparation

Express 400g400\text{g} as a percentage of 2kg2\text{kg}.

Verified Answer

20%20\%

Solving: Convert units to match: 2kg=2000g2\text{kg} = 2000\text{g}. Now calculate percentage: 4002000×100%=15×100%=20%\frac{400}{2000} \times 100\% = \frac{1}{5} \times 100\% = 20\%

Exam Preparation

JAMB UTME Choose the option that has the same vowel sound as "Seat"

Verified Answer

Key / Meat

WASSCE Idiomatic Expressions ("With a grain of salt" implies skepticism)

Exam Preparation

Calculate the scalar product (dot product) of vectors a=3i+4j\mathbf{a} = 3\mathbf{i} + 4\mathbf{j} and b=2i1j\mathbf{b} = 2\mathbf{i} - 1\mathbf{j}

Verified Answer

2

Solving: Multiply matching direction coefficients: (axbx)+(ayby)=(3×2)+(4×1)=64=2(a_x \cdot b_x) + (a_y \cdot b_y) = (3 \times 2) + (4 \times -1) = 6 - 4 = 2.

Exam Preparation

If 15%15\% of a number is 45, find the complete number.

Verified Answer

300

Solving: Let the number be xx. 15100×x=45    15x=4500    x=450015=300\frac{15}{100} \times x = 45 \implies 15x = 4500 \implies x = \frac{4500}{15} = 300

Exam Preparation

If 6 identical textbooks cost ₦9,000, how much will 10 of these textbooks cost?

Verified Answer

₦15,000

Solving: Find the cost of a single book: 90006=1500\frac{9000}{6} = 1500. Multiply by 10 books: 1500×10=15,0001500 \times 10 = ₦15,000

Exam Preparation

JAMB UTME Choose the word with the correct stress pattern: CATASTROPHE

Verified Answer

ca-TAS-tro-phe

UTME Oral English (Stress on the second syllable for this noun format)

Exam Preparation

Convert 451045_{10} to a binary number (base 2)

Verified Answer

1011012101101_2

Solving: Divide continuously by 2 and track remainders: 45/2=22 R 145/2 = 22 \text{ R } 1; 22/2=11 R 022/2 = 11 \text{ R } 0; 11/2=5 R 111/2 = 5 \text{ R } 1; 5/2=2 R 15/2 = 2 \text{ R } 1; 2/2=1 R 02/2 = 1 \text{ R } 0; 1/2=0 R 11/2 = 0 \text{ R } 1. Read upwards: 1011012101101_2.

Exam Preparation

Calculate the total surface area of a solid sphere of radius 7 cm7\text{ cm}. [Take π=227\pi = \frac{22}{7}]

Verified Answer

616 cm2616\text{ cm}^2

Context: The surface area formula for a sphere is A=4πr2A = 4\pi r^2:A=4×227×72=4×227×49=4×22×7=616 cm2A = 4 \times \frac{22}{7} \times 7^2 = 4 \times \frac{22}{7} \times 49 = 4 \times 22 \times 7 = 616\text{ cm}^2

Exam Preparation

Find the Lowest Common Multiple (LCM) of 12, 15, and 18.

Verified Answer

180

Solving: Prime factors: 12=22×312 = 2^2 \times 3, 15=3×515 = 3 \times 5, 18=2×3218 = 2 \times 3^2. Take the highest powers of all prime factors involved: 22×32×5=4×9×5=1802^2 \times 3^2 \times 5 = 4 \times 9 \times 5 = 180.

Exam Preparation

Figures of Speech: What figure of speech is "The wind whispered through the trees"?

Verified Answer

Personification

Exam Preparation

Figures of Speech: What figure of speech is "Time is a thief"?

Verified Answer

Metaphor

Explanation: Direct comparison without using "as" or "like."

Exam Preparation

A student measured the length of a desk as 2.5m2.5\text{m} instead of the actual length of 2.4m2.4\text{m}. Calculate the percentage error.

Verified Answer

4.17%4.17\%

Solving: Error=2.52.4=0.1\text{Error} = 2.5 - 2.4 = 0.1. Percentage Error=ErrorActual×100%=0.12.4×100%=4.166...%4.17%\text{Percentage Error} = \frac{\text{Error}}{\text{Actual}} \times 100\% = \frac{0.1}{2.4} \times 100\% = 4.166...\% \approx 4.17\%.

Exam Preparation

Find the gradient (slope) of the line joining points A(2,5)A(2, 5) and B(4,13)B(4, 13)

Verified Answer

4

Solving: Gradient m=y2y1x2x1=13542=82=4\text{Gradient } m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{13 - 5}{4 - 2} = \frac{8}{2} = 4

Exam Preparation

Evaluate the definite integral: 13(2x+3)dx\int_{1}^{3} (2x + 3) \,dx

Verified Answer

14

Context: Integrate the function first: (2x+3)dx=x2+3x\int (2x + 3) \,dx = x^2 + 3x. Now evaluate it between the limits 1 and 3:[32+3(3)][12+3(1)]=[9+9][1+3]=184=14\left[3^2 + 3(3)\right] - \left[1^2 + 3(1)\right] = [9 + 9] - [1 + 3] = 18 - 4 = 14

Exam Preparation

Simplify the expression: 212+1341182\frac{1}{2} + 1\frac{3}{4} - 1\frac{1}{8}

Verified Answer

3183\frac{1}{8}

Solving: Convert to improper fractions: 52+7498\frac{5}{2} + \frac{7}{4} - \frac{9}{8}. Find the LCM of 2, 4, and 8, which is 8: 20+1498=258=318\frac{20 + 14 - 9}{8} = \frac{25}{8} = 3\frac{1}{8}

Exam Preparation

Find the 15th term of the Arithmetic Progression (A.P.): 3,7,11,15,...3, 7, 11, 15, ...

Verified Answer

59

Solving: First term a=3a = 3, common difference d=4d = 4. Formula: Tn=a+(n1)d    T15=3+(14×4)=3+56=59T_n = a + (n-1)d \implies T_{15} = 3 + (14 \times 4) = 3 + 56 = 59

Exam Preparation

Find the mean of the following set of test scores: 12,15,18,13,17,20,1412, 15, 18, 13, 17, 20, 14

Verified Answer

15.57

Context: Calculate the sum of the observations and divide by the total count (n=7n=7):\text{Sum} = 12 + 15 + 18 + 13 + 17 + 20 + 14 = 109$$$$\text{Mean} = \frac{109}{7} \approx 15.57

Exam Preparation

WAEC WASSCE Fill the blank: The dynamic young manager is looking forward to _______ the new branch next month

Verified Answer

Managing / Taking over

WASSCE Lexis (The phrase "looking forward to" must be followed by a gerund/noun

Exam Preparation

Express 0.03750.0375 as a fraction in its lowest terms

Verified Answer

380\frac{3}{80}

Solving: Write as a fraction: 37510000\frac{375}{10000}. Divide both numerator and denominator by their HCF (125): 375÷12510000÷125=380\frac{375 \div 125}{10000 \div 125} = \frac{3}{80}

Exam Preparation

Rationalize the denominator of the expression: 63\frac{6}{\sqrt{3}}.

Verified Answer

232\sqrt{3}

Solving: Multiply both numerator and denominator by 3\sqrt{3}: 6×33×3=633=23\frac{6 \times \sqrt{3}}{\sqrt{3} \times \sqrt{3}} = \frac{6\sqrt{3}}{3} = 2\sqrt{3}

Exam Preparation

Find the sum of the interior angles of a regular hexagon

Verified Answer

720720^\circ

Context: The formula for the sum of interior angles of an n-sided polygon is (n2)×180(n - 2) \times 180^\circ. For a hexagon, n=6n = 6:(62)×180=4×180=720(6 - 2) \times 180^\circ = 4 \times 180^\circ = 720^\circ

Exam Preparation

Find the mean deviation of the numbers: 4,7,104, 7, 10

Verified Answer

2

Context: First, find the arithmetic mean: 4+7+103=213=7\frac{4+7+10}{3} = \frac{21}{3} = 7. Next, calculate the absolute deviations from the mean: 47=3\vert{}4-7\vert{}=3, 77=0\vert{}7-7\vert{}=0, 107=3\vert{}10-7\vert{}=3. Mean of deviations:3+0+33=63=2\frac{3 + 0 + 3}{3} = \frac{6}{3} = 2

Exam Preparation

Which ancient empire was renowned for its intricate bronze casting techniques used for royal regalia, dating back to at least the 13th century?

Verified Answer

The Benin Empire

Exam Prep: West African History Senior Secondary syllabus

Exam Preparation

Calculus: Find the gradient of the curve y=x24x+5y = x^2 - 4x + 5 at the point where x=3x = 3

Verified Answer

2

Solving: Find the derivative function first: dydx=2x4\frac{dy}{dx} = 2x - 4. Substitute target value x=3x = 3: 2(3)4=64=22(3) - 4 = 6 - 4 = 2

Exam Preparation

If 23x+15x=41x23_x + 15_x = 41_x, find the value of the base xx

Verified Answer

Base 6

Context:23x+15x=41x23_x + 15_x = 41_xConvert to base 10:(2x+3)+(x+5)=4x+13x+8=4x+1x=7(2x + 3) + (x + 5) = 4x + 1 \\ 3x + 8 = 4x + 1 \\ x = 7Wait, let us re-evaluate: 2(6)+3+1(6)+5=15+11=262(6)+3 + 1(6)+5 = 15+11 = 26. 4(6)+1=254(6)+1 = 25. Let's solve the linear equation correctly: 3x+8=4x+1    x=73x + 8 = 4x + 1 \implies x = 7. Base is 7

Exam Preparation

Find the value of xx for which the rational function f(x)=2x+53x9f(x) = \frac{2x + 5}{3x - 9} is undefined

Verified Answer

3

Context: A fractional function becomes undefined when its denominator values equal 0. Set the lower boundary formula to 0:3x9=0    3x=9    x=33x - 9 = 0 \implies 3x = 9 \implies x = 3

Exam Preparation

Evaluate the expression x24x2x2\frac{x^2 - 4}{x^2 - x - 2} to its simplest form.

Verified Answer

x+2x+1\frac{x + 2}{x + 1}

Context: Factorize the numerator using difference of two squares, and factorize the denominator:(x2)(x+2)(x2)(x+1)\frac{(x - 2)(x + 2)}{(x - 2)(x + 1)}Canceling out the common factor (x2)(x - 2) leaves:x+2x+1\frac{x + 2}{x + 1}

Exam Preparation

Find the cube root of 216216

Verified Answer

66

Solving: Prime factorize 216: 23×332^3 \times 3^3. Taking the cube root leaves: 2×3=62 \times 3 = 6. Check: 6×6×6=2166 \times 6 \times 6 = 216.

Exam Preparation

WAEC WASSCE Complete the expression: The assignment was quite difficult, but I managed to get through _______ it

Verified Answer

With

WASSCE Phrasal Verbs standard syntax testing.

Exam Preparation

16 JAMB UTME Choose the option nearest in meaning to adroit

Verified Answer

Skillful / Clever

UTME Vocabulary assessment testing complex adjectives

Exam Preparation

A boy buys a school bag for ₦4,000 and sells it for ₦4,800. What is his percentage profit?

Verified Answer

20%20\%

Solving: Profit=4,8004,000=800\text{Profit} = 4,800 - 4,000 = 800. Percentage Profit=8004000×100%=15×100%=20%\text{Percentage Profit} = \frac{800}{4000} \times 100\% = \frac{1}{5} \times 100\% = 20\%.

Exam Preparation

A bag contains 4 red balls and 6 blue balls. If two balls are drawn at random with replacement, find the probability that both are red.

Verified Answer

425\frac{4}{25}

Solving: Total balls =10= 10. P(Red)=410=25\text{P(Red)} = \frac{4}{10} = \frac{2}{5}. Since drawn with replacement, probabilities remain independent: 25×25=425\frac{2}{5} \times \frac{2}{5} = \frac{4}{25}

Exam Preparation

WAEC WASSCE Complete the sentence: If I had known you were coming, I _______ have baked a cake

Verified Answer

Would

WASSCE Conditional Clauses (Type 3 conditional requires past perfect + would have)

Idioms & Meanings

The lizard that jumped from the high iroko tree said he would praise himself if no one else did.

Verified Answer

It means you should recognize your own achievements and be proud of your efforts, even if others don't notice or celebrate you

Meaning: Emphasizes self-worth and self-validation

Exam Preparation

NECO SSCE Choose the correct option: The new policies are quite different _______ the old ones

Verified Answer

From

SSCE Prepositions (Standard English rule: objects differ from each other, not than)

Exam Preparation

Calculate the area of a circle whose diameter is 14cm14\text{cm}. (Take π=227\pi = \frac{22}{7})

Verified Answer

154cm2154\text{cm}^2

Solving: Radius r=142=7cmr = \frac{14}{2} = 7\text{cm}. Area=πr2=227×7×7=22×7=154cm2\text{Area} = \pi r^2 = \frac{22}{7} \times 7 \times 7 = 22 \times 7 = 154\text{cm}^2

Exam Preparation

JAMB UTME Choose the correct interpretation: The contractor turned a deaf ear to our complaints

Verified Answer

He completely ignored the complaints

UTME Idioms and Idiomatic Expressions

Exam Preparation

Sentence Structure: Identify the error: "He don't like beans."

Verified Answer

He doesn't like beans

Explanation: Describing someone who keeps rather than gives.

Exam Preparation

Convert 11011211011_2 to a base 10 integer

Verified Answer

27

Solving: Expand powers: (1×24)+(1×23)+(0×22)+(1×21)+(1×20)=16+8+0+2+1=27(1 \times 2^4) + (1 \times 2^3) + (0 \times 2^2) + (1 \times 2^1) + (1 \times 2^0) = 16 + 8 + 0 + 2 + 1 = 27

Exam Preparation

WAEC WASSCE Fill the blank: We should have arrived by now, _______ we?

Verified Answer

Shouldn't

WASSCE Question Tags (Positive statements take a negative tag)

Exam Preparation

Find the 15th term of the Arithmetic Progression (A.P.): 5,9,13,17,5, 9, 13, 17, \dots

Verified Answer

61

Context: The first term a=5a = 5 and the common difference d=95=4d = 9 - 5 = 4. Using the formula for the nth term Tn=a+(n1)dT_n = a + (n-1)d:T15=5+(151)4=5+(14×4)=5+56=61T_{15} = 5 + (15 - 1)4 = 5 + (14 \times 4) = 5 + 56 = 61

Exam Preparation

Share ₦5,000 between Chidi and Taiwo in the ratio 2:32:3. How much does Taiwo get?

Verified Answer

₦3,000

Solving: Total ratio parts =2+3=5= 2 + 3 = 5. Taiwo's share =35×5,000=3×1,000=3,000= \frac{3}{5} \times 5,000 = 3 \times 1,000 = ₦3,000

Exam Preparation

Solve the system of inequalities: 2x152x - 1 \le 5 and x+3>1x + 3 > 1

Verified Answer

2<x3-2 < x \le 3

Solving: First equation: 2x6    x32x \le 6 \implies x \le 3. Second equation: x>2x > -2. Combined solution range is 2<x3-2 < x \le 3.

Exam Preparation

yy varies inversely as xx. If y=4y=4 when x=3x=3, find the value of yy when x=6x=6

Verified Answer

2

Solving: Variation equation: y=kx    k=yx=4×3=12y = \frac{k}{x} \implies k = y \cdot x = 4 \times 3 = 12. Now find yy when x=6x=6: y=126=2y = \frac{12}{6} = 2

Exam Preparation

A desktop computer depreciates by 15%15\% each year. If its initial value is N200,000\text{N}200,000, find its value after 2 years

Verified Answer

N144,500\text{N}144,500

Using the compound depreciation formula A=P(1r)2A = P(1 - r)^2:A = 200000 \times (1 - 0.15)^2$$$$A = 200000 \times (0.85)^2 = 200000 \times 0.7225 = 144500

Exam Preparation

Vocabulary: What does 'Pragmatic' mean?

Verified Answer

Practical or Realistic

English Language exam questions while dealing with things sensibly and realistically.

Exam Preparation

If sinθ=35\sin \theta = \frac{3}{5} and θ\theta is acute, find the value of tanθ\tan \theta

Verified Answer

34\frac{3}{4}

Solving: Using a standard 3-4-5 right triangle, the adjacent side is 5232=4\sqrt{5^2 - 3^2} = 4. tanθ=OppositeAdjacent=34\tan \theta = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{3}{4}

Exam Preparation

Differentiate the function with respect to xx: y=4x35x2+2x7y = 4x^3 - 5x^2 + 2x - 7.

Verified Answer

12x210x+212x^2 - 10x + 2

Solving: Apply power rule formula ddx(axn)=naxn1    (3×4)x2(2×5)x1+2=12x210x+2\frac{d}{dx}(ax^n) = n \cdot ax^{n-1} \implies (3 \times 4)x^2 - (2 \times 5)x^1 + 2 = 12x^2 - 10x + 2.

Exam Preparation

Make tt the subject of the formula: v=u+atv = u + at.

Verified Answer

t=vuat = \frac{v - u}{a}

Context: Subtract uu from both sides:vu=atv - u = atDivide both sides by the acceleration variable aa:t=vuat = \frac{v - u}{a}

Exam Preparation

Solve the quadratic equation for xx: 2x25x3=02x^2 - 5x - 3 = 0

Verified Answer

x=3x = 3 or x=12x = -\frac{1}{2}

Context: Factorize by splitting the middle term:2x26x+x3=02x(x3)+1(x3)=0(2x+1)(x3)=0    x=3 or 122x^2 - 6x + x - 3 = 0 \\ 2x(x - 3) + 1(x - 3) = 0 \\ (2x + 1)(x - 3) = 0 \implies x = 3 \text{ or } -\frac{1}{2}

Exam Preparation

What is the historical significance of the 'Golden Stool' (Sika Dwa Kofi) in the Ashanti Kingdom?

Verified Answer

It is believed to house the collective soul of the Ashanti nation and serves as the ultimate symbol of unity and royal authority

History Exam Questions

Exam Preparation

Divide the standard form value 6.4×1076.4 \times 10^7 by 2.0×1032.0 \times 10^3

Verified Answer

3.2×1043.2 \times 10^4

Context: Divide the coefficients and subtract the indices:6.42.0×1073=3.2×104\frac{6.4}{2.0} \times 10^{7-3} = 3.2 \times 10^4

Exam Preparation

JAMB UTME Choose the option nearest in meaning to the underlined word: The president given a magnanimous speech

Verified Answer

Generous / Forgiving

UTME Synonyms. Magnanimous means very generous or forgiving towards a rival.

Exam Preparation

Common Errors: He is senior than me. Wrong

Verified Answer

He is senior to me

Explanation: "Senior," "Junior," "Superior" take "to," not "than."

Exam Preparation

Two fair dice are tossed together once. Find the probability of getting a total sum of 4

Verified Answer

112\frac{1}{12}

Context: Total sample space when tossing two dice =6×6=36= 6 \times 6 = 36. The combinations that sum up to 4 are: (1,3),(2,2),(3,1)(1,3), (2,2), (3,1) (3 outcomes).Probability=336=112\text{Probability} = \frac{3}{36} = \frac{1}{12}

Exam Preparation

In a class of 50 students, 30 speak Yoruba, 25 speak Igbo, and 10 speak both languages. How many speak neither language?

Verified Answer

5

Solving: Using Venn formula: N(YI)=N(Y)+N(I)N(YI)=30+2510=45N(Y \cup I) = N(Y) + N(I) - N(Y \cap I) = 30 + 25 - 10 = 45. Neither language =5045=5= 50 - 45 = 5

Exam Preparation

Find the coordinates of the midpoint of the line segment joining the points A(2,5)A(-2, 5) and B(4,9)B(4, 9)

Verified Answer

(1,7)(1, 7)

Context: Use the midpoint formula M=(x1+x22,y1+y22)M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right):M=(2+42,5+92)=(22,142)=(1,7)M = \left(\frac{-2 + 4}{2}, \frac{5 + 9}{2}\right) = \left(\frac{2}{2}, \frac{14}{2}\right) = (1, 7)

Exam Preparation

NECO SSCE Identify the grammatical name for the underlined clause: The boy who stole the text book has been suspended.

Verified Answer

Adjectival / Relative Clause

SSCE Comprehension & Grammar. It qualifies the noun "The boy"

Exam Preparation

Grammar: Change the sentence from direct to indirect : He said, "I am happy"

Verified Answer

He said that he was happy

English Language exam questions on Pronouns and tenses shift in reported speech.

Exam Preparation

The third term of a Geometric Progression (G.P.) is 18 and the sixth term is 486. Find the common ratio rr

Verified Answer

3

Context: Use the nth term formula Tn=arn1T_n = ar^{n-1}. We have ar2=18ar^2 = 18 and ar5=486ar^5 = 486. Divide the two expressions:ar5ar2=48618    r3=27    r=273=3\frac{ar^5}{ar^2} = \frac{486}{18} \implies r^3 = 27 \implies r = \sqrt[3]{27} = 3

Exam Preparation

IELTS Academic Complete the sentence using the correct form: Dynamic changes in modern technology ______ recontinuous upskilling

Verified Answer

Require

IELTS Grammar & Writing consistency. "Changes" is plural, requiring a plural verb

Exam Preparation

An equilateral triangle has sides of length 8 cm8\text{ cm}. Find its perpendicular height$

Verified Answer

43 cm4\sqrt{3}\text{ cm}

Context: Dropping a vertical line bisects the base into two parts of 4 cm4\text{ cm} each. Using Pythagoras' theorem:h=8242=6416=48=16×3=43 cmh = \sqrt{8^2 - 4^2} = \sqrt{64 - 16} = \sqrt{48} = \sqrt{16 \times 3} = 4\sqrt{3}\text{ cm}

Exam Preparation

Spelling: Which is correct: "Separate" or "Seperate"?

Verified Answer

Separate

Remember: There is 'a rat' in sep-a-rat-e.

Exam Preparation

Find the derivative dydx\frac{dy}{dx} of the algebraic function: y=3x35x2+2x7y = 3x^3 - 5x^2 + 2x - 7.

Verified Answer

9x210x+29x^2 - 10x + 2

Context: Apply the basic power rule of differentiation ddx(axn)=anxn1\frac{d}{dx}(ax^n) = anx^{n-1} term by term:dydx=(3×3)x31(5×2)x21+2=9x210x+2\frac{dy}{dx} = (3 \times 3)x^{3-1} - (5 \times 2)x^{2-1} + 2 = 9x^2 - 10x + 2

Exam Preparation

IELTS General Identify the incorrect preposition: She has been working in this international firm since five years

Verified Answer

Replace "since" with "for"

IELTS Lexical Resource (Use 'for' for total durations/periods of time)

Exam Preparation

Round off 0.0045670.004567 to 2 significant figures.

Verified Answer

0.00460.0046

Solving: Non-zero counting starts at 4. The first two significant figures are 4 and 5. Look at the next digit (6), which rounds 5 up to 6. Output is 0.00460.0046

Exam Preparation

A bag contains 4 red balls and 6 blue balls. If a ball is picked at random, what is the probability that it is red?

Verified Answer

25\frac{2}{5}

Context: Total number of outcomes =4+6=10= 4 + 6 = 10. Number of successful red outcomes =4= 4:Probability=410=25\text{Probability} = \frac{4}{10} = \frac{2}{5}

Exam Preparation

Evaluate the determinant of the matrix (4235)\begin{pmatrix} 4 & 2 \\ 3 & 5 \end{pmatrix}.

Verified Answer

14

Solving: Determinant calculation rule for a 2x2 matrix: (adbc)    (4×5)(2×3)=206=14(ad - bc) \implies (4 \times 5) - (2 \times 3) = 20 - 6 = 14

Exam Preparation

Deduct 110121101_2 from 11100211100_2.

Verified Answer

10011210011_2

Context: Align the columns in binary subtraction:11100211012=10011211100_2 - 1101_2 = 10011_2

Exam Preparation

Find the length of the hypotenuse of a right-angled triangle with side lengths 5cm5\text{cm} and 12cm12\text{cm}.

Verified Answer

13cm13\text{cm}

Solving: Apply Pythagoras: c2=a2+b2    c2=52+122=25+144=169c^2 = a^2 + b^2 \implies c^2 = 5^2 + 12^2 = 25 + 144 = 169. c=169=13cmc = \sqrt{169} = 13\text{cm}

Exam Preparation

Grammar: Fill in: "Neither the teacher nor the students ____ present." (was/were)

Verified Answer

Were

Explanation: The verb agrees with the subject closer to it

Exam Preparation

Find the determinant of the 2×22 \times 2 matrix P=(4325)P = \begin{pmatrix} 4 & 3 \\ 2 & 5 \end{pmatrix}

Verified Answer

14

Context: The determinant of a matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix} is evaluated as adbcad - bc:det(P)=(4×5)(3×2)=206=14\det(P) = (4 \times 5) - (3 \times 2) = 20 - 6 = 14

Exam Preparation

Find the angle of elevation of the sun when a vertical pole of height 10 m10\text{ m} casts a shadow of length 10 m10\text{ m} on level ground

Verified Answer

4545^\circ

Context: Let the angle of elevation be θ\theta. Using basic trigonometry tanθ=OppositeAdjacent\tan \theta = \frac{\text{Opposite}}{\text{Adjacent}}:tanθ=1010=1    θ=tan1(1)=45\tan \theta = \frac{10}{10} = 1 \implies \theta = \tan^{-1}(1) = 45^\circ

Exam Preparation

WAEC WASSCE Complete the idiom: He is an unreliable fellow; you should take everything he says with a grain of _______.

Verified Answer

Salt

WASSCE Idiomatic Expressions ("With a grain of salt" implies skepticism).

Exam Preparation

If cosθ=45\cos \theta = \frac{4}{5} and θ\theta is an acute angle, find the value of tanθ\tan \theta

Verified Answer

34\frac{3}{4}

Context: Using a right-angled triangle where adjacent =4= 4 and hypotenuse =5= 5, find the opposite side using Pythagoras' theorem:Opposite=5242=2516=9=3\text{Opposite} = \sqrt{5^2 - 4^2} = \sqrt{25 - 16} = \sqrt{9} = 3

Exam Preparation

WASSCE Fill the gap: You cannot drive a car _______ you possess a valid driver’s license

Verified Answer

Unless

WASSCE Conjunctions and conditional linkers

Exam Preparation

Evaluate without tables: log216+log327log525\log_{2} 16 + \log_{3} 27 - \log_{5} 25.

Verified Answer

5

Solving: Simplify each block: log224=4\log_2 2^4 = 4; log333=3\log_3 3^3 = 3; log552=2\log_5 5^2 = 2. Combined equation evaluation: 4+32=54 + 3 - 2 = 5

Exam Preparation

NECO SSCE Complete the phrase: By the time the police arrived, the armed robbers _______ escaped.

Verified Answer

Had

SSCE Past Perfect Tense sequence tracking events before another past action

Exam Preparation

What is the remainder when x25x+7x^2 - 5x + 7 is divided by (x2)(x - 2)?

Verified Answer

1

Solving: Apply Remainder Theorem by substituting x=2x = 2 into the polynomial expression: (2)25(2)+7=410+7=1(2)^2 - 5(2) + 7 = 4 - 10 + 7 = 1

Exam Preparation

Express 0.00034720.0003472 in standard scientific form correct to 3 significant figures

Verified Answer

3.47×1043.47 \times 10^{-4}

Move the decimal point 4 places to the right to get 3.4723.472. The 4th digit is 2, so round down.3.47×1043.47 \times 10^{-4}

Exam Preparation

If the internal angles of a triangle are in the ratio 2:3:52:3:5, calculate the size of the largest angle

Verified Answer

9090^\circ

Solving: Sum of angles in a triangle =180= 180^\circ. Total ratio parts =2+3+5=10= 2+3+5=10. Largest share =510×180=90= \frac{5}{10} \times 180^\circ = 90^\circ

Exam Preparation

Calculate the volume of a cylinder with radius 3.5cm3.5\text{cm} and height 10cm10\text{cm}. (Take π=227\pi = \frac{22}{7})

Verified Answer

385cm3385\text{cm}^3

Solving: Volume=πr2h=227×3.5×3.5×10=227×12.25×10=385cm3\text{Volume} = \pi r^2 h = \frac{22}{7} \times 3.5 \times 3.5 \times 10 = \frac{22}{7} \times 12.25 \times 10 = 385\text{cm}^3

Exam Preparation

If x2kx+16x^2 - kx + 16 is a perfect square, find the positive value of the constant kk

Verified Answer

8

Context: For a quadratic expression to be a perfect square, its discriminant must equal zero (b24ac=0b^2 - 4ac = 0):(-k)^2 - 4(1)(16) = 0 \implies k^2 - 64 = 0$$$$k^2 = 64 \implies k = \sqrt{64} = 8

Exam Preparation

Evaluate the definite integral: 133x2dx\int_{1}^{3} 3x^2 \,dx

Verified Answer

26

Solving: Integrate function: [x3]13[x^3]_1^3. Substitute boundaries into derived expression: (33)(13)=271=26(3^3) - (1^3) = 27 - 1 = 26

Exam Preparation

Simplify the expression: 314×(223÷156)3\frac{1}{4} \times \left(2\frac{2}{3} \div 1\frac{5}{6}\right)

Verified Answer

48114\frac{8}{11}

Context: Convert to improper fractions:\frac{13}{4} \times \left(\frac{8}{3} \div \frac{11}{6}\right)$$$$\frac{13}{4} \times \left(\frac{8}{3} \times \frac{6}{11}\right) = \frac{13}{4} \times \frac{16}{11} = \frac{52}{11} = 4\frac{8}{11}

Exam Preparation

Calculate the volume of a cylinder with a base radius of 3.5 cm3.5\text{ cm} and a height of 10 cm10\text{ cm}. [Take π=227\pi = \frac{22}{7}]

Verified Answer

385 cm3385\text{ cm}^3

Context: The volume of a cylinder is given by V=πr2hV = \pi r^2 h:V=227×(3.5)2×10=227×12.25×10=385 cm3V = \frac{22}{7} \times (3.5)^2 \times 10 = \frac{22}{7} \times 12.25 \times 10 = 385\text{ cm}^3

Exam Preparation

Find the standard deviation of the simple dataset: 3,5,7,93, 5, 7, 9

Verified Answer

5\sqrt{5} (or 2.24\approx 2.24)

Solving: Mean =244=6= \frac{24}{4} = 6. Squares of deviations from mean: (36)2=9(3-6)^2=9, (56)2=1(5-6)^2=1, (76)2=1(7-6)^2=1, (96)2=9(9-6)^2=9. Variance =9+1+1+94=204=5= \frac{9+1+1+9}{4} = \frac{20}{4} = 5. Standard Deviation =Variance=5= \sqrt{\text{Variance}} = \sqrt{5}.

Exam Preparation

JAMB UTME Choose the option opposite in meaning to the underlined word: The manager's stringent policies alienated the staff

Verified Answer

Lenient or Flexible

UTME English Lexis (Antonyms). Stringent means strict or precise

Exam Preparation

Calculate the angle subtended at the center of a circle of radius 6cm6\text{cm} by an arc of length 4.4cm4.4\text{cm}. (Take π=227\pi = \frac{22}{7})

Verified Answer

4242^\circ

Solving: Arc length=θ360×2πr    4.4=θ360×2×227×6    θ=4.4×360×724×22=42\text{Arc length} = \frac{\theta}{360} \times 2\pi r \implies 4.4 = \frac{\theta}{360} \times 2 \times \frac{22}{7} \times 6 \implies \theta = \frac{4.4 \times 360 \times 7}{24 \times 22} = 42^\circ

Exam Preparation

Solve the simultaneous linear equations for xx and yy: 3x+y=73x + y = 7 and x2y=0x - 2y = 0

Verified Answer

x=2,y=1x = 2, y = 1

Context: From the second equation, express xx as x=2yx = 2y. Substitute this value into the first equation:3(2y)+y=7    6y+y=7    7y=7    y=13(2y) + y = 7 \implies 6y + y = 7 \implies 7y = 7 \implies y = 1Substituting y=1y = 1 back gives x=2(1)=2x = 2(1) = 2.

Exam Preparation

WAEC WASSCE Fill the gap: Neither the principal nor the teachers _______ present at the briefing yesterday

Verified Answer

Were

WASSCE Lexis and Structure (Concord rule: verb agrees with the closer subject 'teachers'

Exam Preparation

TOEFL iBT Choose the structure that best completes the sentence: Not only _______ beautiful, but it is also highly functional.

Verified Answer

Is the design

TOEFL Structure & Inversion rules (Negative expressions at the start invert the subject/verb)

Exam Preparation

Find the mean of the following set of student test scores: 8,12,5,15,108, 12, 5, 15, 10

Verified Answer

10

Solving: Sum the values: 8+12+5+15+10=508 + 12 + 5 + 15 + 10 = 50. Divide by total count (5 elements): Mean=505=10\text{Mean} = \frac{50}{5} = 10.

Exam Preparation

Convert 1011102101110_2 to a base ten number.

Verified Answer

46

Expand using powers of 2 from right to left starting at 0:(1 \times 2^5) + (0 \times 2^4) + (1 \times 2^3) + (1 \times 2^2) + (1 \times 2^1) + (0 \times 2^0)$$$$32 + 0 + 8 + 4 + 2 + 0 = 46

Exam Preparation

Find the roots of the quadratic equation: x27x+12=0x^2 - 7x + 12 = 0

Verified Answer

x=3x = 3 or x=4x = 4

Solving: Factorize: x23x4x+12=0    x(x3)4(x3)=0    (x4)(x3)=0x^2 - 3x - 4x + 12 = 0 \implies x(x-3) - 4(x-3) = 0 \implies (x-4)(x-3) = 0. Roots are 3 and

Exam Preparation

Solve for xx if logx64=3\log_{x} 64 = 3

Verified Answer

4

Solving: Convert to index form: x3=64x^3 = 64. We know 64=4364 = 4^3. Therefore, x3=43    x=4x^3 = 4^3 \implies x = 4.

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