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Question

Evaluate the definite integral: ∫13(2x+3) dx\int_{1}^{3} (2x + 3) \,dx

Verified Answer

14

Explanation & Step-by-Step Solving

Context: Integrate the function first: ∫(2x+3) dx=x2+3x\int (2x + 3) \,dx = x^2 + 3x. Now evaluate it between the limits 1 and 3:[32+3(3)]−[12+3(1)]=[9+9]−[1+3]=18−4=14\left[3^2 + 3(3)\right] - \left[1^2 + 3(1)\right] = [9 + 9] - [1 + 3] = 18 - 4 = 14

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