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Question

Find the 15th term of the Arithmetic Progression (A.P.): 3,7,11,15,...3, 7, 11, 15, ...

Verified Answer

59

Explanation & Step-by-Step Solving

Solving: First term a=3a = 3, common difference d=4d = 4. Formula: Tn=a+(n1)d    T15=3+(14×4)=3+56=59T_n = a + (n-1)d \implies T_{15} = 3 + (14 \times 4) = 3 + 56 = 59

Topic Tags

Exam aration and answersWAEC Exam arationJAMB Exam arationacademic problems

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