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Question

Find the 15th term of the Arithmetic Progression (A.P.): 5,9,13,17,…5, 9, 13, 17, \dots

Verified Answer

61

Explanation & Step-by-Step Solving

Context: The first term a=5a = 5 and the common difference d=9−5=4d = 9 - 5 = 4. Using the formula for the nth term Tn=a+(n−1)dT_n = a + (n-1)d:T15=5+(15−1)4=5+(14×4)=5+56=61T_{15} = 5 + (15 - 1)4 = 5 + (14 \times 4) = 5 + 56 = 61

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Exam aration and answersWAEC Exam arationJAMB Exam arationacademic problems

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