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Question

If x2kx+16x^2 - kx + 16 is a perfect square, find the positive value of the constant kk

Verified Answer

8

Explanation & Step-by-Step Solving

Context: For a quadratic expression to be a perfect square, its discriminant must equal zero (b24ac=0b^2 - 4ac = 0):(-k)^2 - 4(1)(16) = 0 \implies k^2 - 64 = 0$$$$k^2 = 64 \implies k = \sqrt{64} = 8

Topic Tags

Exam aration and answersWAEC Exam arationJAMB Exam arationacademic problems

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